Asked by rd0543293 | 19th Jun, 2022, 10:51: AM

Expert Answer:

I1 = I2 = 10 A 
d = 2 m 
Force per unit length is given as, 
F equals space fraction numerator mu subscript 0 I subscript 1 I subscript 2 over denominator 2 pi d end fraction space equals space fraction numerator 4 pi cross times 10 to the power of negative 7 end exponent cross times 10 space cross times space 10 over denominator 2 cross times pi cross times 2 end fraction equals 10 to the power of negative 5 end exponent space N divided by m space
As the current flows in same direction there will be attractive force between the two wires. 

Answered by Shiwani Sawant | 20th Jun, 2022, 01:25: PM