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CBSE Class 12-science Answered

Calculate the amount of energy released during the a decay of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.   Atomic mass of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. = 238.05079 u Atomic mass of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. = 234.04363 u Atomic mass of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. = 4.00260 u 1u = 931.5 Me V/c2 Is this decay spontaneous? Give reason.
Asked by Topperlearning User | 02 Jun, 2015, 09:11: AM
answered-by-expert Expert Answer

The amount of energy released during a decay,

Q = Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.

Q = [238.05079 - 234.04363 - 4.00260] x 931.5 MeV

Q = 0.00456 x 931.5 = 4.25 MeV

No net energy is required for this reaction because energy is already produced by the conversion of lost mass energy. Because of this, the reaction is spontaneous.

Answered by | 02 Jun, 2015, 11:11: AM
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