Bacl2 + Na3Po4 - Nacl + Ba3(Po4)2
 
 
If 0.5 moles of BAcl2 is mixed with 0.2 moles of Na3Po4 the maximum no.of moles of Ba3(Po4)2that can be formed is
 
 

Asked by vedant sharma | 30th Oct, 2014, 04:01: PM

Expert Answer:

Balanced reaction is:

3BaCl2 + 2Na3PO4   →   Ba3(PO4)2 + 6NaCl

3 moles of BaCl2 react with 2 moles of Na3PO4 to give 1 mole of Ba3(PO4)2
The mole ratio between BaCl2 and Na3PO4 is
n(BaCl2):n(Na3PO4)=3:2

The ratio of these compounds in the given mixture is 0.5/0.2 = 5:2 > 3:2.

Hence, the BaCl2 is in excess and the Na3PO4 is the limiting reactant.

Now, 2 moles of Na3PO4 give 1 mole of Ba3(PO4)2
So, 0.2 moles of Na3PO4 will give (1/2) x 0.2 = 0.1 mole of Ba3(PO4)2
So, number of moles of Ba3(PO4)2 formed = 0.1

Answered by Arvind Diwale | 31st Oct, 2014, 10:56: AM