CBSE Class 10 Answered
Bacl2 + Na3Po4 - Nacl + Ba3(Po4)2
If 0.5 moles of BAcl2 is mixed with 0.2 moles of Na3Po4 the maximum no.of moles of Ba3(Po4)2that can be formed is
Asked by vedant sharma | 30 Oct, 2014, 04:01: PM
Expert Answer
Balanced reaction is:
3BaCl2 + 2Na3PO4 → Ba3(PO4)2 + 6NaCl
3 moles of BaCl2 react with 2 moles of Na3PO4 to give 1 mole of Ba3(PO4)2
The mole ratio between BaCl2 and Na3PO4 is
n(BaCl2):n(Na3PO4)=3:2
The ratio of these compounds in the given mixture is 0.5/0.2 = 5:2 > 3:2.
Hence, the BaCl2 is in excess and the Na3PO4 is the limiting reactant.Now, 2 moles of Na3PO4 give 1 mole of Ba3(PO4)2
So, 0.2 moles of Na3PO4 will give (1/2) x 0.2 = 0.1 mole of Ba3(PO4)2
So, number of moles of Ba3(PO4)2 formed = 0.1
Answered by Arvind Diwale | 31 Oct, 2014, 10:56: AM
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