at what angle do forces P+Q and P-Q act so that their resultant is

Asked by  | 18th Dec, 2009, 01:14: PM

Expert Answer:

R = (F12 + F22 +2F1F2cosθ)1/2

cosθ = (R2 - F12 - F22 )/(2F1F2)

= (3P2+Q2 - (P+Q)2 - (P-Q)2)/(2(P+Q)(P-Q))

= (3P2+Q2 -2P2 - 2Q2 )/(2(P+Q)(P-Q))

= (P2-Q2)/(2(P2-Q2))

= 1/2

Hence the angle is 600

Regards,

Team,

TopperLearning. 

Answered by  | 18th Dec, 2009, 06:30: PM

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