Arrange cyclohexane, KCL, CH3OH, CH3CN in order of their increasing solubility in n octane.
Asked by j4jaigupta1998
| 9th Jun, 2015,
10:00: AM
The solubility of a non-polar solute is more than that of a polar solute in the n-octane. n-octane is a non-polar solvent.
Cyclohexane : non-polar
KCl : ionic
CH3OH : polar covalent
CH3CN : weakly polar covalent
The order of increasing polarity is:
Cyclohexane < CH3CN < CH3OH < KCl
Reason:
Cyclohexane and n-Octane are non polar solvents and hence mix with each other in all proportions.
KCl is an ionic compound and n-octane is non polar, therefore do not dissolve in n-octane.
Methyl alcohol and methyl cyanide both are polar compounds, but methyl alcohol is more polar, and methyl cyanide is less polar. So methyl cyanide will dissolve more in n-octane .
Therefore, the order of increasing solubility is:
KCl < CH3OH < CH3CN < Cyclohexane
The solubility of a non-polar solute is more than that of a polar solute in the n-octane. n-octane is a non-polar solvent.
Cyclohexane : non-polar
KCl : ionic
CH3OH : polar covalent
CH3CN : weakly polar covalent
The order of increasing polarity is:
Cyclohexane < CH3CN < CH3OH < KCl
Reason:
Cyclohexane and n-Octane are non polar solvents and hence mix with each other in all proportions.
KCl is an ionic compound and n-octane is non polar, therefore do not dissolve in n-octane.
Methyl alcohol and methyl cyanide both are polar compounds, but methyl alcohol is more polar, and methyl cyanide is less polar. So methyl cyanide will dissolve more in n-octane .
Therefore, the order of increasing solubility is:
KCl < CH3OH < CH3CN < Cyclohexane
Answered by Hanisha Vyas
| 10th Jun, 2015,
10:42: AM
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