Arrange cyclohexane, KCL, CH3OH, CH3CN in order of their increasing solubility in n octane.


Asked by j4jaigupta1998 | 9th Jun, 2015, 10:00: AM

Expert Answer:

The solubility of a non-polar solute is more than that of a polar solute in the n-octane. n-octane is a non-polar solvent.

Cyclohexane  : non-polar

KCl                : ionic

CH3OH           : polar covalent

CH3CN           : weakly polar covalent

The order of increasing polarity is:

Cyclohexane < CH3CN <  CH3OH < KCl


Cyclohexane and n-Octane are non polar solvents and hence mix with each other in all proportions.

KCl is an ionic compound and n-octane is non polar, therefore do not dissolve in n-octane.

Methyl alcohol and methyl cyanide both are polar compounds, but methyl alcohol is more polar, and methyl cyanide is less polar. So methyl cyanide will dissolve more in n-octane .

Therefore, the order of increasing solubility is:

KCl < CH3OH < CH3CN < Cyclohexane

Answered by Hanisha Vyas | 10th Jun, 2015, 10:42: AM

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