NEET Class neet Answered
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Asked by rekhapremkumar25 | 27 Aug, 2021, 07:06: AM
Expert Answer
Distance dn of nth charge from origin is given as
dn = 2(n-1) m
Electric field E due to infinite number of charges is given as
where K = 1/(4πεo ) is Coulomb's constant
Hence E = K q [ 1 + (1/4) + (1/16) +(1/64) ....................... to ∞ ] N/C = K q Sn N/C
Bracketted term in above expression is geometric series with first term is 1 and common multipier is (1/4) .
Sn is sum of geometric series
Sn = 1 / [ 1 - (1/4) ] = 4/3 m-2
Hence electric field E = (4/3) K q
Answered by Thiyagarajan K | 27 Aug, 2021, 11:45: AM
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