Request a call back

Join NOW to get access to exclusive study material for best results

NEET Class neet Answered

answer
question image
Asked by rekhapremkumar25 | 27 Aug, 2021, 07:06: AM
answered-by-expert Expert Answer
Distance dn of nth charge from origin is given as
 
dn = 2(n-1) m
 
Electric field E due to infinite number of charges is given as
 
begin mathsize 14px style E space equals space sum from n equals 1 to infinity of K space cross times q over 2 to the power of left parenthesis 2 n minus 2 right parenthesis end exponent space N divided by C end style
where K = 1/(4πεo ) is Coulomb's constant
 
Hence E = K q [ 1 + (1/4) + (1/16) +(1/64) ....................... to ∞ ]  N/C = K q Sn N/C
 
Bracketted term in above expression is geometric series with first term is 1 and common multipier is (1/4) .
 
Sn is sum of geometric series
 
Sn =  1 / [ 1 - (1/4) ] = 4/3   m-2
 
Hence electric field E = (4/3) K q
Answered by Thiyagarajan K | 27 Aug, 2021, 11:45: AM
NEET neet - Physics
Asked by zfaima704 | 19 Jul, 2024, 14:29: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Physics
Asked by nandiniaishu99 | 26 Jun, 2024, 18:05: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Physics
Asked by bhaktisheetal1234 | 18 Mar, 2024, 23:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Physics
Asked by sakshusharma631 | 22 Feb, 2024, 10:24: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Physics
Asked by luckyankitg | 17 Dec, 2023, 18:39: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Physics
Asked by slavanya19102005 | 18 Nov, 2023, 20:29: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Physics
Asked by premprakash780014 | 17 Jan, 2023, 21:09: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Are You a Teacher or a Parent Seeking Customised Tests? Click here
×