CBSE Class 8 Answered

We know that,

the product of two numbers = product of their HCF and LCM

here, HCF × LCM = 9 × 819 = 7371.

Since the unit number is 1, the number cannot a multiple of 2 or 5.

The number must be an odd number and a multiple of 9.

So, 27 and 63 are the possibiliies of numbers.

If one number is 27 then the other number is 7371/27 = 273

Factors of 27 = 3  x 9 and factors of 273 = 3  x 91.

Here, the HCF is 3 and LCM = 3 x 9 x 91 = 2457.

So, this pair is not acceptable.

 If one number is 63 then the other number is 7371/63 = 117.

Factors of 63 = 3 x 3 x 7  and 117 = 3 x 3 x 13

HCF = 3 x3 = 9

LCM - 3 x 3 x 7 x 13 = 819.

So, this pair is the answer.

Therefore, the required two numbers are 63 and 117.