CBSE Class 9 Answered

An object starting from rest travels 20m in the first 2s and 160m in the next 4s. What will be the velocity after 7s from the start?

Asked by sudip.mondal09 | 20 May, 2021, 10:37: AM

Expert Answer

Given data:

u = 0 m/s; s = 20 mt = 2 s

We use the formula s = ut + (1/2)at²

Substituting the values, we get

a = 10 m/s²

At t = 7 seconds

v = u + a t ,

→ v = 0 + a t

= 10 x 7

→ v = 70 m/s

Answered by Shiwani Sawant | 20 May, 2021, 12:22: PM

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CBSE Class 9 Answered

Given data:

u = 0 m/s; s = 20 mt = 2 s

We use the formula s = ut + (1/2)at²

Substituting the values, we get

a = 10 m/s²

At t = 7 seconds

v = u + a t ,

→ v = 0 + a t

= 10 x 7

→ v = 70 m/s

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CBSE Class 9 Answered

Given data: u = 0 m/s; s = 20 mt = 2 s We use the formula s = ut + (1/2)at2 Substituting the values, we get a = 10 m/s2 At t = 7 seconds v = u + a t , → v = 0 + a t = 10 x 7 → v = 70 m/s

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Motion - Exam Decoded - 6

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Given data:

u = 0 m/s; s = 20 mt = 2 s

We use the formula s = ut + (1/2)at²

Substituting the values, we get

a = 10 m/s²

At t = 7 seconds

v = u + a t ,

→ v = 0 + a t

= 10 x 7

→ v = 70 m/s