CBSE Class 10 Answered
An object is placed at a distance of 4cm from a concave mirror of focal length lcm. Find the nature and position of the image
Asked by sreekumar1974 | 02 Aug, 2019, 11:54: AM
u = -4 cm (object distance)
f = - 1 cm
v = ?
By mirror formula,
![1 over f equals 1 over v plus 1 over u
fraction numerator 1 over denominator negative 1 end fraction equals 1 over v plus fraction numerator 1 over denominator negative 4 end fraction
fraction numerator begin display style 1 end style over denominator begin display style v end style end fraction equals space minus 1 minus space fraction numerator 1 over denominator negative 4 end fraction equals negative 1 space plus space 0.25 space equals space space minus 0.75 space
T h u s comma space
v space equals space fraction numerator 1 over denominator negative 0.75 end fraction equals space minus 1.33 space c m space](https://images.topperlearning.com/topper/tinymce/cache/141f92c07ed021116e859a52b79d75af.png)
Thus, the position of an image is 1.33 cm.
Thus, it will be formed between focus and centre of curvature.
thus, the nature of image is real, inverted and diminished.
Answered by Shiwani Sawant | 02 Aug, 2019, 13:04: PM
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