An object 2 cm high is placed at a distance of 16 cm from mirror that produces a real image 3 cm high. (a) Find the position of the image (b) What is the focal length of the mirror?
Asked by Topperlearning User | 2nd May, 2014, 01:32: PM
(a) Position of object, height of object and image are 16 cm, 2 cm and 3 cm respectively.
m = h'/h
In this, height of image will be taken negative as it is a real image.
m = -3/2 = -1.5,
Also, m = -v/u
Therefore, -1.5 = -v/(u)
v = -1.5 x 16 = -24 cm
(b) Focal length
u = -16 cm, v = -24 cm, focal length, f = ?
1/v+1/u = 1/f
-1/24 + (-1/16) = 1/f
-5/48 = 1/f
f = -9.6 cm
Answered by | 2nd May, 2014, 03:32: PM
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