an aircraft is flying at a height of 3400 m above the ground.if the angle subtended at a given

Asked by  | 26th Jul, 2009, 12:42: AM

Expert Answer:

The aircraft takes 10s to go from one point (say A) to the other (say B) and AB subtands an angle of 30o at the point of observation (say O) .So, ABO forms a triangle.Now let OC be perpendicualr bisector drawn from O to AB(i.e. actually the height).

Then in right trianle, OAC

AC = OC tan 15o = 3400 x 0.2679 = 911 m

so, AB = 2 x 911 = 1822 m

Now, the speed of aircraft , v = AB / t = 1822 / 10 = 182.2 m/s.

Answered by  | 26th Jul, 2009, 12:03: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.