an aircraft is flying at a height of 3400 m above the ground.if the angle subtended at a given
Asked by | 26th Jul, 2009, 12:42: AM
The aircraft takes 10s to go from one point (say A) to the other (say B) and AB subtands an angle of 30o at the point of observation (say O) .So, ABO forms a triangle.Now let OC be perpendicualr bisector drawn from O to AB(i.e. actually the height).
Then in right trianle, OAC
AC = OC tan 15o = 3400 x 0.2679 = 911 m
so, AB = 2 x 911 = 1822 m
Now, the speed of aircraft , v = AB / t = 1822 / 10 = 182.2 m/s.
Answered by | 26th Jul, 2009, 12:03: PM
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