CBSE Class 12-science Answered
A uniform electric field of magnitude 100kV/m is directed upwards. Perpendicular to E & directed into the page there exists a uniform magnetic field= 0.5T. A beam of +q particles enters this region. What should be the chosen sped of the particles for which the particles will not be deflected by the crossed electric & magnetic field.
Asked by padmakrith | 17 Jun, 2013, 11:21: AM
Expert Answer
force exerted by magnetic field will be in direction perpendicular to both direction of motion an the direction of magnetic field. this force will be opposed by the force due to electric field.
if velocity = v
force due to mag. field, Fm = q(vxB) = 0.5qv
force due to electric field = qE = 100q x 103 N
thus equating these two we can find the value of v for no deflection.
Answered by | 17 Jun, 2013, 12:15: PM
Concept Videos
CBSE 12-science - Physics
Asked by himanshurawat5823 | 08 Mar, 2024, 01:24: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by anubhutiupadhaya | 06 Mar, 2023, 04:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by rd0543293 | 19 Jun, 2022, 10:51: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by arjunsah797 | 26 Mar, 2022, 09:10: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by arjunsah797 | 16 Mar, 2022, 02:07: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by shantanumail24 | 09 Mar, 2022, 07:04: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by yashrajgharte24.12dgatl | 25 Oct, 2021, 06:53: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by pushpakumari291279 | 01 Oct, 2021, 11:08: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by yashrajgharte24.12dgatl | 24 Sep, 2021, 04:21: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by yashrajgharte24.12dgatl | 24 Aug, 2021, 07:23: AM
ANSWERED BY EXPERT