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CBSE Class 9 Answered

A submarine emits a sonar pulse,which returns from an underwater cliff in 1.02s.If the speed of sound in salt water is 1531m/s,how far away is the cliff?
Asked by | 12 Jan, 2013, 12:34: PM
answered-by-expert Expert Answer
Time taken by the sonar pulse to return, t = 1.02 s Speed of sound in salt water, v = 1531 m s?1 Distance of the cliff from the submarine = Speed of sound × Time taken
Distance of the cliff from the submarine=1.02 x 1531 =1561.62m
Distance travelled by the sonar pulse during its transmission and reception in water = 2 × Actual distance = 2d
Actual distance, d = (Distance of the cliff from the submarin)/2 = 1561.62/2 = 780.31 m
Answered by | 12 Jan, 2013, 06:49: PM

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