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A stone
Asked by satyamthakur7570 | 21 Dec, 2020, 09:04: PM

Let S is depth of well and the dropped stone takes t1 seconds to reach the water surface. The we haveS = (1/2)×9.8×t12 = 4.9×t12  ....................(1)let t2 be the time taken for the sound to reach observer. then we havet2 = S/330 ..................(2)substiute for S in (2) using (1)t2 = (4.9×t12)/330 = 0.014 t12 ........(3)we are given t1+t2 = 2.5 s ...........(4)using (3) in (4),  t1 + 0.014 t12  = 2.5  ...(5)by solving this quadratic equation (5) , we get t1 = 2.418 second.Hence the depth S can be obtained from (1) : S = 4.9 x (2.418)2 = 28.648 m

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