A stone tied to the end of a string 80cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25s, what is the magnitude and direction of acceleration of stone?
Asked by toppin | 14th Sep, 2010, 12:31: PM
In one revolution angle swapped = 2∏ radian
therefore in 14 revolution angle swapped= 14 * 2∏ radian
Time taken = 25 sec.
Hence angular speed ω =
= 3.52 rad/sec
Length of string L = 0.8 m
magnitude of acceleration = ω2L
Direction will be towards the center of circle.
Answered by | 14th Sep, 2010, 01:37: PM
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