CBSE Class 9 Answered
a stone is allowed to fall from the top of a tower of height 200m and at the same time an another stone is projected vertically upwards from the ground with a velocity of 50 metre per second calculate where and when the two stones will meet. ( take g = 10 metre per second square)
Asked by jy3037485 | 21 Mar, 2021, 11:05: AM
The time taken by the body sent upward to meet the top body
is 200/50 = 4 seconds.
The acceleration produced each second to the top body which is dropped is also a deceleration produced to the velocity of stone thrown upward.
4.9 x 4 x 4 = 78.4 m
From the top 200 - 78.4 = 121.6 m
Thus,
is 200/50 = 4 seconds.
The acceleration produced each second to the top body which is dropped is also a deceleration produced to the velocity of stone thrown upward.
4.9 x 4 x 4 = 78.4 m
From the top 200 - 78.4 = 121.6 m
Thus,
Both stones meet at 121.6 m
Answered by Shiwani Sawant | 23 Mar, 2021, 23:37: PM
Application Videos
Concept Videos
CBSE 9 - Physics
Asked by varshuparekh | 03 Jun, 2024, 18:34: PM
CBSE 9 - Physics
Asked by janhavisoni2099 | 02 Oct, 2023, 17:20: PM
CBSE 9 - Physics
Asked by sagrawal0081 | 18 Aug, 2023, 17:04: PM
CBSE 9 - Physics
Asked by ketkiparasgandhi | 05 Jul, 2023, 20:02: PM
CBSE 9 - Physics
Asked by adityatripathi84418 | 02 May, 2023, 22:29: PM
CBSE 9 - Physics
Asked by rsaranya658 | 30 Jun, 2022, 14:44: PM
CBSE 9 - Physics
Asked by poornimaram165 | 21 Jun, 2022, 21:16: PM
CBSE 9 - Physics
Asked by saanidhyapatil | 16 Feb, 2022, 13:23: PM
CBSE 9 - Physics
Asked by pradeepkumarbhegde5175 | 12 Jan, 2022, 23:25: PM