a soln cntains h2so4 20% by mass its density is 1.10g/ml what would be its molality

Asked by soha | 11th Aug, 2012, 09:26: PM

Expert Answer:

Since it is 20% by mass H2SO4, then mass H2SO4 in 100 g solution =  20 g
and mass H2O in 100 g = 80 g H2O = 0.080 kg

So, moles H2SO4 in 100 g solution = mass / molar mass = 20 g / 98.086 g/mol = 0.2039 mol


molality = moles solute / kg solvent
= 0.2039 mol / 0.080 kg
= 2.5 m

Answered by  | 19th Aug, 2012, 12:21: PM

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