Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

a soln cntains h2so4 20% by mass its density is 1.10g/ml what would be its molality
Asked by soha | 11 Aug, 2012, 09:26: PM
answered-by-expert Expert Answer
Since it is 20% by mass H2SO4, then mass H2SO4 in 100 g solution =  20 g
and mass H2O in 100 g = 80 g H2O = 0.080 kg

So, moles H2SO4 in 100 g solution = mass / molar mass = 20 g / 98.086 g/mol = 0.2039 mol


molality = moles solute / kg solvent
= 0.2039 mol / 0.080 kg
= 2.5 m
Answered by | 19 Aug, 2012, 12:21: PM
CBSE 12-science - Chemistry
Asked by soumyaranjanchhatria21 | 29 May, 2024, 08:20: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by chetanrakshit06 | 05 May, 2024, 02:51: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by sameerteli003 | 08 Apr, 2024, 11:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by rashmij34 | 27 Feb, 2024, 04:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by sagarmishra | 27 Feb, 2024, 04:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by kalandi.charan.407 | 08 Feb, 2024, 01:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by premkhare2006 | 24 Jan, 2024, 09:50: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by saritanohar22 | 13 Jan, 2024, 01:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×