# CBSE Class 10 Answered

**A rocket is in the form of circular closed at the ler end and a cone of same radius is attached to the top.The radius of the clylinder is 2.5m ,it's height is 21m and the slant height of the cone is 8m Find the T.S.A of rocket**

Asked by ybproduction256 | 27 Nov, 2023, 00:26: AM

Expert Answer

Let R = 2.5 m and H = 21 m be the radius and height of cylindrical part of rocket respectively .

Let L = 8 m be the slant height of cone .

Total surface area = π R

^{2}+ (2πR) H + π R Lwhere the first term is the area of bottom surface , second term is the area of curved surface

of cylinder and the third term is lateral surface area of cone .

Total surface area = π R ( R + 2 H + L )

Total surface area = π × 2.5 ( 2.5 + 42 + 8 ) m

^{2}= 412 m^{2}
Answered by Thiyagarajan K | 27 Nov, 2023, 08:28: AM

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