A proton and an alpha particle, both initially at rest, are (suitably) accelerated so as to have the same kinetic energy. What is the ratio of their de-Broglie wavelengths?

Asked by prernamehta | 20th Jan, 2012, 08:31: PM

Expert Answer:

K.E.=P2/2M-------(1)
 
?=h/P--------(2)
 
?=h/?K.E.*2M-------(3)
 
?1/?2=?M2/?M1--------(4)
 
?1/?2=?4M1/M1       ( Mass of alpha particle is 4 times of mass of proton)
 
?1/?2=2
 
wavelength of proton(?1) is double of wavelength of alpha particle(?2).
 

Answered by  | 21st Jan, 2012, 10:39: AM

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