CBSE Class 12-science Answered

Focal length of objective, fo = 1 cmObject distance for objective, uo = ?Image distance for objective, vo = ?
Focal length of eye piece, fe = 5 cmObject distance for objective, ue = ?Image distance for objective, ve = -D = -25 cm (Least distance of distinct vision)
Distance between objective and eye piece, L = 12.2 cm
Since the image by objective is formed between the objective and the eye piece at a distance vo from objective and this image acts a virtual object for eye piece which is located at a distance ue from the eye piece,the length of microscope,L = |vo| + |ue| = 12.2 cm
Using the lens formula for eye piece.
1/fe = 1/ve - 1/ue

1/ue = 1/ve - 1/fe

1/ue = 1/-25 - 1/5 = -6/25

ue = -25/6 cm = -4.17 cm
We know that L = ​ |vo| + |ue| = 12.2 cmSo |vo| = 12.2 - ​ |ue| = 12.2 - 4.17 = 8.03 cm
Now using the lens formula for objective,1/fo = 1/vo - 1/uo

1/uo​ =  1/vo - 1/fo

1/uo = 1/8.03 - 1/1

1/uo = -0.875uo = -1.142 cm.
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