ICSE Class 8 Answered
A car of mass 1000kg is moving with a certain speed when a constant breaking force of 1000 N acts on it for 5 seconds and the speed of car reduces to half its original speed. Find the further time required to stop the car if the same constant force acts.
Asked by mkp400 | 17 Dec, 2017, 12:26: PM
Retardation = Force/mass = 1000 N/ 1000 kg = 1 m/s2
in 5 seconds initial speed v0 reduces to (v0/2). then ![begin mathsize 12px style v subscript 0 over 2 equals v subscript 0 cross times 5 space minus space 1 half cross times 1 cross times 25 comma space t h i s space g i v e s space v subscript 0 equals space 25 over 11 end style](https://images.topperlearning.com/topper/tinymce/cache/28550e143a49b3206323224f8c3d9716.png)
![begin mathsize 12px style v subscript 0 over 2 equals v subscript 0 cross times 5 space minus space 1 half cross times 1 cross times 25 comma space t h i s space g i v e s space v subscript 0 equals space 25 over 11 end style](https://images.topperlearning.com/topper/tinymce/cache/28550e143a49b3206323224f8c3d9716.png)
now the speed is (25/22) m/s. Required time to stop the car completely is given by
![begin mathsize 12px style 0 space equals space 25 over 22 t space minus space 1 half cross times 1 cross times t squared space comma space t h i s space g i v e s space t space equals space 2 3 over 11 space s end style](https://images.topperlearning.com/topper/tinymce/cache/0c221240aa0d27ea758c8f83d0c7f20f.png)
Answered by | 17 Dec, 2017, 13:32: PM
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