A car moving at speed v I's stopped by retarding force F in distance x. If the speed of car becomes 3 times, the force needed to stop it within same distance x is what. Answer with complete solutions.

Asked by ranirajesh786 | 27th May, 2019, 02:04: PM

Expert Answer:

Let,s assume that the mass of car be m
 
Final velocity of car V=0
initial velocity U=v
 
using
 v squared equals u squared plus 2 a s
0 equals v squared plus 2 open parentheses fraction numerator negative F over denominator m end fraction close parentheses x
v squared equals 2 open parentheses F over m close parentheses x minus negative negative negative negative negative negative negative negative left parenthesis 1 right parenthesis
if the velocity of the car is made 3 times 
open parentheses 3 v close parentheses squared equals fraction numerator 2 F to the power of apostrophe x over denominator m end fraction
9 v squared equals fraction numerator 2 F to the power of apostrophe x over denominator m end fraction minus negative negative negative negative negative negative negative negative left parenthesis 2 right parenthesis
 
On substitution we get
F to the power of apostrophe equals 9 F

Answered by Utkarsh Lokhande | 27th May, 2019, 02:39: PM