CBSE Class 9 Answered
A car moving at speed v I's stopped by retarding force F in distance x. If the speed of car becomes 3 times, the force needed to stop it within same distance x is what. Answer with complete solutions.
Asked by ranirajesh786 | 27 May, 2019, 14:04: PM
Let,s assume that the mass of car be m
Final velocity of car V=0
initial velocity U=v
using
![v squared equals u squared plus 2 a s
0 equals v squared plus 2 open parentheses fraction numerator negative F over denominator m end fraction close parentheses x
v squared equals 2 open parentheses F over m close parentheses x minus negative negative negative negative negative negative negative negative left parenthesis 1 right parenthesis](https://images.topperlearning.com/topper/tinymce/cache/fc609d5f558a14973f57633453021724.png)
![v squared equals u squared plus 2 a s
0 equals v squared plus 2 open parentheses fraction numerator negative F over denominator m end fraction close parentheses x
v squared equals 2 open parentheses F over m close parentheses x minus negative negative negative negative negative negative negative negative left parenthesis 1 right parenthesis](https://images.topperlearning.com/topper/tinymce/cache/fc609d5f558a14973f57633453021724.png)
if the velocity of the car is made 3 times
![open parentheses 3 v close parentheses squared equals fraction numerator 2 F to the power of apostrophe x over denominator m end fraction
9 v squared equals fraction numerator 2 F to the power of apostrophe x over denominator m end fraction minus negative negative negative negative negative negative negative negative left parenthesis 2 right parenthesis](https://images.topperlearning.com/topper/tinymce/cache/cb0274639db49723e372d0ceceae648d.png)
On substitution we get
![F to the power of apostrophe equals 9 F](https://images.topperlearning.com/topper/tinymce/cache/8d0f76c651b900b40bed5e61a8e86f16.png)
Answered by Utkarsh Lokhande | 27 May, 2019, 14:39: PM
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