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CBSE Class 9 Answered

A car is travelling with a speed of 36km/h. The driver applies the brakes and retards the car uniformly. The car is stopped in 5 seconds. Find i) Retardation of the car ii) Distance travelled before it is stopped.
Asked by thrishithlr930 | 03 Jul, 2021, 08:00: PM
Expert Answer
u = 36 km/h = 10 m/s 
v =0
t = 5 s 
 
i) v = u + at 
0 = 10 + a x 5 
Thus, 
a = -10/5 
a = 2 m/s2 
Thus, retardation of the car is 2 m/s2 
 
ii) 
s = ut + 1/2 at2 
s = 10 x 5 + (1/2) x (-2) x 52 
s = 50 - 25 = 25 m 
Answered by Shiwani Sawant | 05 Jul, 2021, 10:15: AM
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