CBSE Class 9 Answered
A car is travelling with a speed of 36km/h. The driver applies the brakes and
retards the car uniformly. The car is stopped in 5 seconds. Find
i) Retardation of the car
ii) Distance travelled before it is stopped.
Asked by thrishithlr930 | 03 Jul, 2021, 08:00: PM
u = 36 km/h = 10 m/s
v =0
t = 5 s
i) v = u + at
0 = 10 + a x 5
Thus,
a = -10/5
a = 2 m/s2
Thus, retardation of the car is 2 m/s2
ii)
s = ut + 1/2 at2
s = 10 x 5 + (1/2) x (-2) x 52
s = 50 - 25 = 25 m
Answered by Shiwani Sawant | 05 Jul, 2021, 10:15: AM
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