A car is travelling with a speed of 36km/h. The driver applies the brakes and retards the car uniformly. The car is stopped in 5 seconds. Find i) Retardation of the car ii) Distance travelled before it is stopped.

Asked by thrishithlr930 | 3rd Jul, 2021, 08:00: PM

Expert Answer:

u = 36 km/h = 10 m/s 
v =0
t = 5 s 
 
i) v = u + at 
0 = 10 + a x 5 
Thus, 
a = -10/5 
a = 2 m/s2 
Thus, retardation of the car is 2 m/s2 
 
ii) 
s = ut + 1/2 at2 
s = 10 x 5 + (1/2) x (-2) x 52 
s = 50 - 25 = 25 m 

Answered by Shiwani Sawant | 5th Jul, 2021, 10:15: AM