ICSE Class 10 Answered
A car along with passengers weighs 2000 kg it accelerates from 36 km per hour to 90 km per hour in 10 seconds calculate a.acceleration b. Distance covered by car while accelerating c. momentum of car after 10 second d.force developed by the engine of car e.Total energy expanded during accelerationf. power of the engine in Kilowatt
Asked by Samrat | 30 Jun, 2018, 07:18: PM
Expert Answer
initial speed = 36 km/hr = 36×(5/18) = 10 m/s ; final speed = 90 km/hr = 90×(5/18) = 25 m/s
(a) acceleration ; formula to be used :- " v = u+a t ", acceleration a = (v-u)/t = (25-10)/10 = 1.5 m/s2
(b) distance ; formula to be used :- " S = u t +(1/2) a t2 " , distance = 10×10 + (1/2)×1.5×10×10 = 175 m
(c) momentum = mass × speed = 2000×25 = 50000 Kgm/s
(d) force = mass × acceleration = 2000×1.5 = 3000 N
(e) Energy = workdone = force ×distance = 3000×175 = 5,25,000 J
(f) Power = Energy /time = 525000/10 = 52500 W = 52.5 kW
Answered by Thiyagarajan K | 02 Jul, 2018, 02:17: PM
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