CBSE Class 9 Answered
A car accelarates uniformly from 18 km to 36 km in 5 seconds. Calculate
(i.)accelaration (ii.)distance covered by the car
Asked by deeptisingh25 | 29 Jun, 2014, 03:32: PM
Expert Answer
We know that acceleration = (v - u) / t
Here initial velocity = 18 km/h , Final velocity = 36 km/h , t = 5 sec
Change in velocity (v -u ) - 36 km/h - 18 km/ h = 18 km / hr .
1.
Distance covered by the car = 37.5 m
Answered by Jyothi Nair | 30 Jun, 2014, 08:45: AM
Application Videos
Concept Videos
CBSE 9 - Physics
Asked by kempersi267k | 01 Jul, 2022, 06:36: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by hd2583188 | 02 Jun, 2022, 05:04: AM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by juhi.panchal | 05 May, 2022, 11:26: AM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by grangerhermione951 | 02 Dec, 2021, 08:32: AM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by psdarshan25082007 | 08 Sep, 2021, 08:14: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by 2103030034 | 28 Aug, 2021, 03:06: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by atmojyotibarman7 | 30 Jul, 2021, 03:27: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by vikaashrajan11 | 28 Jul, 2021, 09:55: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by jainpranav33047 | 20 Jul, 2021, 09:28: AM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by ansh231206bhatia | 29 May, 2021, 03:42: PM
ANSWERED BY EXPERT