A car accelarates uniformly from 18 km h to the power of minus 1 end exponent to 36 km h to the power of minus 1 end exponentin 5 seconds. Calculate
(i.)accelaration  (ii.)distance covered by the car

Asked by deeptisingh25 | 29th Jun, 2014, 03:32: PM

Expert Answer:

We know that acceleration = (v - u) / t

Here initial velocity = 18 km/h , Final velocity = 36 km/h , t = 5 sec

Change in velocity (v -u ) - 36 km/h - 18 km/ h = 18 km / hr .

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Distance covered by the car = 37.5 m

Answered by Jyothi Nair | 30th Jun, 2014, 08:45: AM

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