ICSE Class 10 Answered
a bullet of mass 10 g travels with speed 500 m/s on striking a wooden target it penetrates 0.5 m inside calculate kinetic energy and resistive force
Asked by Samrat | 28 Jun, 2018, 11:41: AM
Kinetic Energy ![begin mathsize 12px style 1 half m space v squared space equals space 1 half cross times 10 cross times 10 to the power of negative 3 end exponent cross times 500 cross times 500 space equals space 1250 space J end style](https://images.topperlearning.com/topper/tinymce/cache/c0cc849fa0fa4cd39fc43baa6421bd2e.png)
![begin mathsize 12px style 1 half m space v squared space equals space 1 half cross times 10 cross times 10 to the power of negative 3 end exponent cross times 500 cross times 500 space equals space 1250 space J end style](https://images.topperlearning.com/topper/tinymce/cache/c0cc849fa0fa4cd39fc43baa6421bd2e.png)
Let a be the retardation produced by wooden target and this retardation is calculated
using the formula "v2 = u2 - 2aS " using final velocity v=0 and initial velocity u = 500 m/s and stopping distance = 0.5 m
![begin mathsize 12px style a space equals space fraction numerator u squared over denominator 2 s end fraction space equals space fraction numerator 500 cross times 500 over denominator 2 cross times 0.5 end fraction space equals space 250000 space m divided by s squared end style](https://images.topperlearning.com/topper/tinymce/cache/cf31239a77e9a06ee6ff44fd637f0f30.png)
Resistive force = mass of bullet × retardation ![begin mathsize 12px style equals space 10 cross times 10 to the power of negative 3 end exponent cross times 25 cross times 10 to the power of 4 space equals space 2500 space N end style](https://images.topperlearning.com/topper/tinymce/cache/cebc6e0a95440009b28ff1948032fea8.png)
![begin mathsize 12px style equals space 10 cross times 10 to the power of negative 3 end exponent cross times 25 cross times 10 to the power of 4 space equals space 2500 space N end style](https://images.topperlearning.com/topper/tinymce/cache/cebc6e0a95440009b28ff1948032fea8.png)
Answered by Thiyagarajan K | 28 Jun, 2018, 14:14: PM
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