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ICSE Class 10 Answered

A body of mass 500 kg is resting on a frictionless surface calculate the distance travelled by it in 10 sec when it is acted upon by a force of 10^-2 N

Asked by Samrat | 29 Jun, 2018, 09:49: PM
Expert Answer
acceleration a  produced on 500 kg mass by 10-2 N force is given by,     a = force/mass = 10-2 / 500 = 0.2×10-4 m/s2
 
distance S moved in 10 sec is calculated using formula " S = (1/2)×a×t2 " , hence S = (1/2)×0.2×10-4 ×10×10 = 1 mm
Answered by Thiyagarajan K | 30 Jun, 2018, 05:59: PM
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