A ball is given simultaneously two velocities , one 10 m/s due east and the other 20 m/s due north-west.Calculate the resultant velocity of the ball
Asked by nooh KHAN | 15th Feb, 2014, 01:41: PM
Expert Answer:
Given that,
V1 = 10 m/s
V2 = 20 m/s
The angle between two velocities = 90 + 45 (∴ one is East and other is North West)
θ = 135?
V2 = V12 + V22 + 2 V1 V2 Cos θ
V2 = 102 + 202 + 2(10) (20) (Cos135)
= 100 + 400 + 400 (- Cos45)
= 500 + 400(-1 /)
= 500 - (400 / 1.414)
V2 = 500 - 282.84 = 217.157
V = 14. 73 m/s
Therefore the resultant velocity of the ball = 14.73 m/s.
Given that,
V1 = 10 m/s
V2 = 20 m/s
The angle between two velocities = 90 + 45 (∴ one is East and other is North West)
θ = 135?
V2 = V12 + V22 + 2 V1 V2 Cos θ
V2 = 102 + 202 + 2(10) (20) (Cos135)
= 100 + 400 + 400 (- Cos45)
= 500 + 400(-1 /)
= 500 - (400 / 1.414)
V2 = 500 - 282.84 = 217.157
V = 14. 73 m/s
Therefore the resultant velocity of the ball = 14.73 m/s.
Answered by | 17th Feb, 2014, 04:39: PM
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