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# CBSE Class 9 Answered

a=-0.5 Speed = 90km/h find distance
Asked by mrohitgarg2008 | 24 May, 2021, 09:02: AM
The question is assumed that initial speed is 90 km/hr,  deceleration is 0.5 m/s2 and what is the distanace travelled.

We need to use equation of motion " v2 = u2 - ( 2 a S ) " , where v is final speed and u is initial speed. Final speed v is zero because the object comes to rest after travelling a distance S with deceleration a .

S = u2 / ( 2 a ) ..................... (1)

Speed 90 km/hr = 90 × ( 5 / 18 ) = 25 m/s

S = ( 25 × 25 ) / ( 2 × 0.5 ) = 625 m

Answered by Thiyagarajan K | 24 May, 2021, 09:13: AM

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