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CBSE Class 11-science Answered

98%H2SO4 soln by mass and has a density Of 1.8 g/ml . Volume Of acid reqd. to make 1lt Of 0.1M H2SO4 soln is-
Asked by harshit.baruah123 | 01 Sep, 2019, 01:32: PM
Expert Answer
98 gram of H2SO4 is dissolved in 100 g of solution.
 
Niumber space of space moles equals fraction numerator Given space Mass over denominator space Mass end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 98 straight g over denominator 98 straight g divided by mol end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1 space straight g divided by mol Density space of space solution equals 1.80 space straight g divided by ml Density equals Mass over Volume Volume equals fraction numerator 100 space straight g over denominator 1.80 space straight g divided by ml end fraction space space space space space space space space space space space space space equals 55.5 space ml Molarity equals fraction numerator 1 cross times 1000 over denominator 55.5 end fraction equals 18 space straight M straight M subscript 1 straight V subscript 1 equals straight M subscript 2 straight V subscript 2 18 cross times straight V subscript 2 equals 0.1 cross times 1000 straight V subscript 2 equals 5.55 ml
Answered by Ravi | 02 Sep, 2019, 01:13: PM

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