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CBSE Class 11-science Answered

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Asked by smanishkumar2002 | 10 Jun, 2018, 10:50: PM
answered-by-expert Expert Answer
It is assumed that the given object is  a rope of length L and Mass M.
 
Acceleration a given to the rope, a = F/M
 
Tension at section A = ( mass of part of rope left to section A ) × acceleration  = begin mathsize 12px style fraction numerator open parentheses L minus x close parentheses over denominator L end fraction cross times M cross times F over M space equals space fraction numerator begin display style open parentheses L minus x close parentheses end style over denominator begin display style L end style end fraction cross times F end style
Answered by Thiyagarajan K | 11 Jun, 2018, 10:41: AM
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