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1.If f(x)=x³+x²-ax+b is divisible by x²-x write the values of a&b 2.If a-b,a,a+b are zeros of polynomial f(x)=2x³-6x²+5x-7,write the value of a.
Asked by CHIDAMBAR | 07 Oct, 2018, 01:21: PM
x³ + x² -ax + b is divisible by x² - x or x(x -1)

x and (x -1) are the factors of x³ + x² -ax + b .

mean x(x - 1) = 0

x = 0 or x - 1 = 0

Therefore x = 0 and x = 1

0 and 1 the zeros of x³ + x² -ax + b.

1. Substituting x = 0, we get

(0)³ + (0)² -a(0) + b = 0
b = 0

2. Substituting x = 1, we get
(1)³ + (1)² - a(1) + b = 0
1 + 1 - a + b = 0
2 - a + 0 = 0
a = 2

a = 2 and b = 0

Therefore value of a=2 and b = 0.

Answered by Yasmeen Khan | 07 Oct, 2018, 05:37: PM

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