1.Find the equation of a straight line passing through the point of intersection of the lines 3x + y - 9=0 and 4x + 3y - 7=0 and perpendicular to the line 5x - 4y + 1=0. 2.Find the equation of the line joining the point of intersection of 3x + 2y + 1=0 and x+y-3=0 to the point of intersection of 3x+2y-1=0 and x+y-5=0.

Asked by R.K. Kumar | 28th Dec, 2012, 05:47: PM

Expert Answer:

the equation of a straight line passing through the point of intersection of the lines 3x + y - 9=0 and 4x + 3y - 7=0

usfamily of lines

(3x + y - 9)+p(4x + 3y - 7)=0

to find p

this is perpendicular to line

5x - 4y + 1=0

so -(3+4p/1+3p)*5/4=-1

solving for p

p=-11/8

so equation of line will be

3x+y-9-11/8(4x+3y-7)=0

4x+5y=1

Answered by  | 28th Dec, 2012, 11:17: PM

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