1)   
2)   
3)   
4)   
 

Asked by Ram Kumar | 22nd Apr, 2014, 11:10: AM

Expert Answer:

Aqueous KOH results into substitution reaction.

Cl3C−CH2−CH3+3KOH(aq)→(OH)3C−CH2−CH3+3KCl

It may be noted that more than one OH group cannot be present on the same carbon atom. In such a case, the compound will be extremely unstable and will readily lose a water molecule to form more stable propionic acid.

(OH)3C−CH2−CH3?HOOC−CH2−CH3+H2O

Thus, propionic acid is the major product along with water molecule.

Hence, the corrrect option is propionic acid (option 2).

Answered by  | 23rd Apr, 2014, 11:39: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.