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CBSE Class 12-science Answered

Using Amperes Circuital law, derive an expression for the magnetic feild along the axis of toroidal solinoid.
Asked by Ayush | 02 Feb, 2015, 08:09: AM
answered-by-expert Expert Answer
Let n be the number of turns per unit length of toroid and I be the current flowing through it. A magnetic field of constant magnitude is set up inside the turns of toroid in the form of concentric circular magnetic field lines. The direction of the magnetic field at a point is given by the tangent to the magnetic field line at that point. 
We draw three circular amperian loops, 1, 2 and 3 of radii r1, r2 and r3 to be traversed in clockwise direction as shown by dashed circles in Fig (b), so that the points P, S and Q may lie on them. The circular area bounded by loops 2 and 3, both cut the toroid. Each turn of current carrying wire is cut once by the loop 2 and twice by the loop 3. Let B1 be the magnitude of magnetic field along loop 1. Line integral of magnetic field B1 along the loop 1 is
 
 
 
 
Answered by Faiza Lambe | 02 Feb, 2015, 03:47: PM

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