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CBSE Class 9 Answered

Triangle ABC has vertices A(0,1),B(-3,0)and C(1,0).If ad is median and G is centroid,then the lenght of AG is...??

Asked by Harshita Singh | 17 Oct, 2015, 01:21: PM
answered-by-expert Expert Answer
C o n s i d e r space t h e space g i v e n space v e r t i c e s space A open parentheses 0 comma 1 close parentheses comma space B open parentheses negative 3 comma 0 close parentheses space a n d space C open parentheses 1 comma 0 close parentheses S i n c e space G space i s space t h e space c e n t r o i d comma space t h e space c o o r d i n a t e s space o f space G space a r e colon space G open parentheses fraction numerator x subscript 1 plus x subscript 2 plus x subscript 3 over denominator 3 end fraction comma fraction numerator y subscript 1 plus y subscript 2 plus y subscript 3 over denominator 3 end fraction close parentheses T h u s comma space G identical to G open parentheses fraction numerator 0 minus 3 plus 1 over denominator 3 end fraction comma fraction numerator 0 plus 0 plus 0 over denominator 3 end fraction close parentheses rightwards double arrow G identical to G open parentheses fraction numerator negative 2 over denominator 3 end fraction comma 0 close parentheses D i s tan c e space A G equals square root of open parentheses fraction numerator negative 2 over denominator 3 end fraction minus 0 close parentheses squared plus open parentheses 0 minus 1 close parentheses squared end root space space space space space space space space space space space space space space space space space space space space equals square root of 4 over 9 plus 1 end root space space space space space space space space space space space space space space space space space space space space equals square root of fraction numerator 4 plus 9 over denominator 9 end fraction end root space space space space space space space space space space space space space space space space space space space space equals square root of 13 over 9 end root space space space space space space space space space space space space space space space space space space space space equals fraction numerator square root of 13 over denominator 3 end fraction u n i t s
Answered by Vimala Ramamurthy | 18 Oct, 2015, 08:06: AM

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