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the vertices of a triangle are A (1,2 , B (5,7) C(11 , 13). find the length of the median passing through the vertices A 

Asked by tarjindersingh55 2nd October 2017, 11:54 AM
Answered by Expert
Answer:
begin mathsize 16px style Let space AD space be space the space median space through space the space vertex space straight A space of space triangle space ABC.
Then comma space straight D space is space the space mid minus point space of space BC.
So comma space the space coordinates space of space straight D space equals space open parentheses fraction numerator 5 plus 11 over denominator 2 end fraction comma space fraction numerator 7 plus 13 over denominator 2 end fraction close parentheses equals open parentheses 16 over 2 comma space 20 over 2 close parentheses equals open parentheses 8 comma space 10 close parentheses
therefore space AD equals square root of open parentheses 1 minus 8 close parentheses squared plus open parentheses 2 minus 10 close parentheses squared end root equals square root of 49 plus 64 end root equals square root of 113 space units end style
Answered by Expert 3rd October 2017, 9:29 AM
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