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CBSE Class 10 Answered

The 27th question...
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Asked by subbukum | 13 Feb, 2020, 12:28: PM
answered-by-expert Expert Answer
The question should be as follows:
The area of a triangle with vertices (a, b+c), (b, a+c) and (c, a+b) is
A r e a space o f space t r i a n g l e equals 1 half open vertical bar x subscript 1 open parentheses y subscript 2 minus y subscript 3 close parentheses plus x subscript 2 open parentheses y subscript 3 minus y subscript 1 close parentheses plus x subscript 3 open parentheses y subscript 1 minus y subscript 2 close parentheses close vertical bar equals 1 half open vertical bar a open parentheses a plus c minus a minus b close parentheses plus b open parentheses a plus b minus b minus c close parentheses plus c open parentheses b plus c minus a minus c close parentheses close vertical bar equals 1 half open vertical bar a open parentheses c minus b close parentheses plus b open parentheses a minus c close parentheses plus c open parentheses b minus a close parentheses close vertical bar equals 1 half open vertical bar a c minus a b plus a b minus b c plus b c minus a c close vertical bar equals 0 H e n c e comma space t h e space a r e a space o f space t h e space t r i a n g l e space i s space 0.
Answered by Renu Varma | 13 Feb, 2020, 01:11: PM

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CBSE 10 - Maths
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The 27th question...
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Asked by subbukum | 13 Feb, 2020, 12:28: PM
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