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CBSE Class 12-science Answered

 
Asked by kvunni hj | 29 Dec, 2014, 09:40: PM
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begin mathsize 14px style Given space that : Distance space between space the space two space slits comma space straight d space equals space 1 mm equals 10 to the power of minus 3 end exponent space straight m Wavelength space of space light comma space straight lambda space equals 6.5 space cross times 10 to the power of minus 7 end exponent space straight m Distance space between space the space slit space and space the space screen comma space straight D space equals space 1 space straight m We space know space that : Position space of space straight n to the power of th space bright space fringe space is space given space by : straight x space equals nλ straight D over straight d space where space straight n space equals space 1 comma 2 comma 3..... and space the space position space of space straight m to the power of th space end exponent dark space fringe space is space given space by : straight x space equals left parenthesis 2 straight m minus 1 right parenthesis straight lambda over 2 straight D over straight d space where space straight m space equals 1 comma 2 comma 3........ The space distance space between space the space bright space and space the space dark space fringe space can space be space obtained space by : straight x space equals space nλ straight D over straight d minus left parenthesis 2 straight n minus 1 right parenthesis straight lambda over 2 straight D over straight d straight x space equals λD over straight d open square brackets straight n minus left parenthesis 2 straight m minus 1 right parenthesis 1 half close square brackets straight x space equals λD over straight d open square brackets straight n minus straight m plus 1 half close square brackets Substituting space the space values space : ie. space here space straight n space equals space 5 space and space straight m space equals space 3 straight x space equals fraction numerator 6.5 space cross times 10 to the power of minus 7 end exponent space straight m cross times 1 space straight m over denominator 10 to the power of minus 3 end exponent space straight m end fraction open square brackets 5 minus 3 plus 1 half close square brackets straight x equals fraction numerator 6.5 space cross times 10 to the power of minus 7 end exponent space straight m cross times 1 space straight m over denominator 10 to the power of minus 3 end exponent space straight m end fraction cross times 5 over 2 straight x space equals 1.625 space cross times 10 to the power of minus 3 end exponent space straight m straight x space equals 1.625 space mm end style
The distance between the 3 rd dark fringe and 5 th bright fringe = 1.625 mm
Answered by Jyothi Nair | 30 Dec, 2014, 09:21: AM

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CBSE 12-science - Physics
find the condition for constructive and destructive interference .how does the intensity depend on the width of slit?  
Asked by shivamtkr7767 | 03 Mar, 2024, 12:45: PM
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CBSE 12-science - Physics
find the intensity at a point on a screen in young double slit experiment where the interfering wave of equal intensity have have a path difference of lemda/4,lemda/3
Asked by tannusharan31 | 05 Nov, 2023, 05:31: PM
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CBSE 12-science - Physics
In Young's double slit experiment, the two slits are separated by 0.28mm and the screen is placed at a distance of 1.4m away from the slits. the distance between the centre fringe and the fifth dark fringe is measured to be 1.35cm . calculate the wavelength of light used. Also find the fringe width if the screen is moved 0.4m towards the slits, for the same experiment set up.
Asked by mrwballari999 | 03 Jan, 2023, 09:33: AM
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CBSE 12-science - Physics
if separation between the two slits is increased till fringes are observed then what will happen to angular separation of fringes (my thought is here  fringes are not observed  and they are increasing till fringes show up ...so until then what will happen to angular width if we increase d-slit separation..does angular width increases or remains same  
Asked by neetaspirantdoctor | 20 May, 2022, 03:57: PM
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CBSE 12-science - Physics
coherent sources
Asked by aryanshahi903 | 09 Apr, 2021, 06:14: AM
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CBSE 12-science - Physics
two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
Asked by nehadevi2728 | 19 Mar, 2021, 03:56: PM
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CBSE 12-science - Physics
We for equal wave intensities the intensity at a point is given by straight I to the power of apostrophe equals 4 Icos squared open parentheses straight ϕ over 2 close parentheses but where does the formula straight I to the power of apostrophe equals Icos squared open parentheses straight ϕ over 2 close parentheses come from??
Asked by deepsmooth41 | 19 Apr, 2020, 01:00: AM
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CBSE 12-science - Physics
Question 15
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Asked by ritikabehera01 | 20 Feb, 2019, 09:56: AM
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CBSE 12-science - Physics
kindly answer
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Asked by jain.pradeep | 18 Feb, 2019, 11:27: PM
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CBSE 12-science - Physics
kindly provide answer pl
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Asked by jain.pradeep | 18 Feb, 2019, 11:03: PM
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