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CBSE Class 12-science Answered

two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
Asked by nehadevi2728 | 19 Mar, 2021, 03:56: PM
Expert Answer
This question is not communicated properly . Intensity of light is not given properly,
 
Let us assume Intensities of coherent light wave be I1 and I2 .
 
Resultant intensity IR is given as
 
begin mathsize 14px style I subscript R space equals space I subscript 1 space plus space I subscript 2 space plus space 2 space square root of I subscript 1 I subscript 2 end root space cos phi end style  .............................(1)
where φ is phase difference between two light wave
 
Phase difference = Path difference × (2π / λ)  = ( λ / 6 ) × ( 2π / λ ) = π/3
 
Resultant intensity IR is given as
 
begin mathsize 14px style I subscript R space equals space I subscript 1 space plus space I subscript 2 subscript space end subscript space plus space 2 space square root of I subscript 1 I subscript 2 end root space cos left parenthesis pi divided by 3 right parenthesis space equals space space I subscript 1 space plus space I subscript 2 subscript space end subscript space plus space square root of I subscript 1 I subscript 2 end root space end style ..........................(2)
 
If intensities of light waves are equal and intensity of each one is I
 
hence we have , I1  = I2  = I  ................(3)
 
By substituting I1 and I2 using eqn.(3) , we rewrite eqn.(2) as ,  IR = 3 I
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