Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
Asked by nehadevi2728 | 19 Mar, 2021, 03:56: PM
answered-by-expert Expert Answer
This question is not communicated properly . Intensity of light is not given properly,
 
Let us assume Intensities of coherent light wave be I1 and I2 .
 
Resultant intensity IR is given as
 
begin mathsize 14px style I subscript R space equals space I subscript 1 space plus space I subscript 2 space plus space 2 space square root of I subscript 1 I subscript 2 end root space cos phi end style  .............................(1)
where φ is phase difference between two light wave
 
Phase difference = Path difference × (2π / λ)  = ( λ / 6 ) × ( 2π / λ ) = π/3
 
Resultant intensity IR is given as
 
begin mathsize 14px style I subscript R space equals space I subscript 1 space plus space I subscript 2 subscript space end subscript space plus space 2 space square root of I subscript 1 I subscript 2 end root space cos left parenthesis pi divided by 3 right parenthesis space equals space space I subscript 1 space plus space I subscript 2 subscript space end subscript space plus space square root of I subscript 1 I subscript 2 end root space end style ..........................(2)
 
If intensities of light waves are equal and intensity of each one is I
 
hence we have , I1  = I2  = I  ................(3)
 
By substituting I1 and I2 using eqn.(3) , we rewrite eqn.(2) as ,  IR = 3 I
Answered by Thiyagarajan K | 19 Mar, 2021, 05:13: PM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 12-science - Physics
find the condition for constructive and destructive interference .how does the intensity depend on the width of slit?  
Asked by shivamtkr7767 | 03 Mar, 2024, 12:45: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
find the intensity at a point on a screen in young double slit experiment where the interfering wave of equal intensity have have a path difference of lemda/4,lemda/3
Asked by tannusharan31 | 05 Nov, 2023, 05:31: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
In Young's double slit experiment, the two slits are separated by 0.28mm and the screen is placed at a distance of 1.4m away from the slits. the distance between the centre fringe and the fifth dark fringe is measured to be 1.35cm . calculate the wavelength of light used. Also find the fringe width if the screen is moved 0.4m towards the slits, for the same experiment set up.
Asked by mrwballari999 | 03 Jan, 2023, 09:33: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
if separation between the two slits is increased till fringes are observed then what will happen to angular separation of fringes (my thought is here  fringes are not observed  and they are increasing till fringes show up ...so until then what will happen to angular width if we increase d-slit separation..does angular width increases or remains same  
Asked by neetaspirantdoctor | 20 May, 2022, 03:57: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
coherent sources
Asked by aryanshahi903 | 09 Apr, 2021, 06:14: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
Asked by nehadevi2728 | 19 Mar, 2021, 03:56: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
We for equal wave intensities the intensity at a point is given by straight I to the power of apostrophe equals 4 Icos squared open parentheses straight ϕ over 2 close parentheses but where does the formula straight I to the power of apostrophe equals Icos squared open parentheses straight ϕ over 2 close parentheses come from??
Asked by deepsmooth41 | 19 Apr, 2020, 01:00: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Question 15
question image
Asked by ritikabehera01 | 20 Feb, 2019, 09:56: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
kindly answer
question image
Asked by jain.pradeep | 18 Feb, 2019, 11:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
kindly provide answer pl
question image
Asked by jain.pradeep | 18 Feb, 2019, 11:03: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×