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two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point Expert Answer
This question is not communicated properly . Intensity of light is not given properly,

Let us assume Intensities of coherent light wave be I1 and I2 .

Resultant intensity IR is given as .............................(1)
where φ is phase difference between two light wave

Phase difference = Path difference × (2π / λ)  = ( λ / 6 ) × ( 2π / λ ) = π/3

Resultant intensity IR is given as ..........................(2)

If intensities of light waves are equal and intensity of each one is I

hence we have , I1  = I2  = I  ................(3)

By substituting I1 and I2 using eqn.(3) , we rewrite eqn.(2) as ,  IR = 3 I
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