CBSE Class 12-science Answered
two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
Asked by nehadevi2728 | 19 Mar, 2021, 03:56: PM
This question is not communicated properly . Intensity of light is not given properly,
Let us assume Intensities of coherent light wave be I1 and I2 .
Resultant intensity IR is given as

where φ is phase difference between two light wave
Phase difference = Path difference × (2π / λ) = ( λ / 6 ) × ( 2π / λ ) = π/3
Resultant intensity IR is given as

If intensities of light waves are equal and intensity of each one is I
hence we have , I1 = I2 = I ................(3)
By substituting I1 and I2 using eqn.(3) , we rewrite eqn.(2) as , IR = 3 I
Answered by Thiyagarajan K | 19 Mar, 2021, 05:13: PM
Concept Videos
CBSE 12-science - Physics
Asked by mrwballari999 | 03 Jan, 2023, 09:33: AM
CBSE 12-science - Physics
Asked by neetaspirantdoctor | 20 May, 2022, 03:57: PM
CBSE 12-science - Physics
Asked by aryanshahi903 | 09 Apr, 2021, 06:14: AM
CBSE 12-science - Physics
Asked by nehadevi2728 | 19 Mar, 2021, 03:56: PM
CBSE 12-science - Physics
Asked by deepsmooth41 | 19 Apr, 2020, 01:00: AM
CBSE 12-science - Physics
Asked by ritikabehera01 | 20 Feb, 2019, 09:56: AM
CBSE 12-science - Physics
Asked by jain.pradeep | 18 Feb, 2019, 11:27: PM
CBSE 12-science - Physics
Asked by jain.pradeep | 18 Feb, 2019, 11:03: PM
CBSE 12-science - Physics
Asked by sparbin0019 | 25 Jan, 2019, 09:21: AM
CBSE 12-science - Physics
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM