CBSE Class 12-science Answered
two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
Asked by nehadevi2728 | 19 Mar, 2021, 15:56: PM
This question is not communicated properly . Intensity of light is not given properly,
Let us assume Intensities of coherent light wave be I1 and I2 .
Resultant intensity IR is given as
![begin mathsize 14px style I subscript R space equals space I subscript 1 space plus space I subscript 2 space plus space 2 space square root of I subscript 1 I subscript 2 end root space cos phi end style](https://images.topperlearning.com/topper/tinymce/cache/d555fd45ea854c95383b5ecdf8897b86.png)
where φ is phase difference between two light wave
Phase difference = Path difference × (2π / λ) = ( λ / 6 ) × ( 2π / λ ) = π/3
Resultant intensity IR is given as
![begin mathsize 14px style I subscript R space equals space I subscript 1 space plus space I subscript 2 subscript space end subscript space plus space 2 space square root of I subscript 1 I subscript 2 end root space cos left parenthesis pi divided by 3 right parenthesis space equals space space I subscript 1 space plus space I subscript 2 subscript space end subscript space plus space square root of I subscript 1 I subscript 2 end root space end style](https://images.topperlearning.com/topper/tinymce/cache/93f1f579c812df7238b4b326dd6eb672.png)
If intensities of light waves are equal and intensity of each one is I
hence we have , I1 = I2 = I ................(3)
By substituting I1 and I2 using eqn.(3) , we rewrite eqn.(2) as , IR = 3 I
Answered by Thiyagarajan K | 19 Mar, 2021, 17:13: PM
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