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CBSE Class 12-science Answered

The mole fraction of a very dilute aqueous solution is 0.05. Calculate the molarity of the solution.
Asked by lekhakarthikeyan | 29 Aug, 2018, 08:06: PM
answered-by-expert Expert Answer
Let space no. of space moles space of space solute space be space apostrophe straight n apostrophe space and space no. of space moles space of space solvent space apostrophe straight N apostrophe space Mole space frcation space of space solute equals fraction numerator straight n over denominator left parenthesis straight n plus straight N right parenthesis end fraction equals 0.05 Mole space frcation space of space solvent space left parenthesis straight H subscript 2 straight O right parenthesis equals fraction numerator straight N over denominator left parenthesis straight n plus straight N right parenthesis end fraction equals 0.95 fraction numerator begin display style fraction numerator straight n over denominator straight n plus straight N end fraction end style over denominator begin display style fraction numerator straight N over denominator left parenthesis straight n plus straight N right parenthesis end fraction end style end fraction equals fraction numerator left parenthesis 0.05 right parenthesis over denominator left parenthesis 0.95 right parenthesis end fraction straight n over straight N equals 1 over 19 space straight N equals fraction numerator Weight over denominator molecular space weight space of space straight H subscript 2 straight O end fraction fraction numerator left parenthesis straight n cross times straight M subscript straight H subscript 2 straight O end subscript right parenthesis over denominator straight W subscript straight H subscript 2 straight O end subscript end fraction equals 1 over 19 straight n over straight W subscript straight H subscript 2 straight O end subscript equals fraction numerator 1 over denominator 19 cross times 18 end fraction Molality equals straight n over straight W subscript straight H subscript 2 straight O end subscript cross times 1000 space space space space space space space space space space space equals fraction numerator 1 over denominator 19 cross times 18 end fraction cross times 1000 Molality equals 2.9 space straight m
 
Molality of the solution is 2.9 m
Answered by Varsha | 05 Sep, 2018, 02:53: PM

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