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# The mass M shown in figure oscillates in simple harmonic motion with aplitude A.The amplitude of point P is

Asked by gunjanparate05 29th November 2019, 5:04 AM

Figure shows the system of two springs which is in oscillatory motion due to Force F.

Let the spring constant of spring-1 be k1 and its amplitude be A1 .
Similarly the spring constant of spring-2 be k2 and its amplitude be A2 .

net Amplitde A = A1 + A2...............(1)

When displacement is maximum,  force acting on each spring is shown in figure.

internal restoring forces acting in spring-2 is k2A2 . Restoring force acting in spring-2 pulls spring-1 .

Since restoring force acting in spring-1 is k1A1 , at the time of maximum displacement,

k1A1 = k2A2  ...................(2)

Using eqn.(1), we write eqn.(2) as,  k1A1 = k2 ( A - A1)

Hence from above eqn., we get , A1 =  [ k2 / (k1 + k2) ] A

Answered by Expert 29th November 2019, 9:31 AM
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Tags: amplitude