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The mass M shown in figure oscillates in simple harmonic motion with aplitude A.The amplitude of point P is
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Asked by gunjanparate05 | 29 Nov, 2019, 05:04: AM
answered-by-expert Expert Answer
 
Figure shows the system of two springs which is in oscillatory motion due to Force F.
 
Let the spring constant of spring-1 be k1 and its amplitude be A1 .
Similarly the spring constant of spring-2 be k2 and its amplitude be A2 .
 
net Amplitde A = A1 + A2...............(1)
 
When displacement is maximum,  force acting on each spring is shown in figure.
 
internal restoring forces acting in spring-2 is k2A2 . Restoring force acting in spring-2 pulls spring-1 .
 
Since restoring force acting in spring-1 is k1A1 , at the time of maximum displacement, 
 
k1A1 = k2A2  ...................(2)
 
Using eqn.(1), we write eqn.(2) as,  k1A1 = k2 ( A - A1)
 
Hence from above eqn., we get , A1 =  [ k2 / (k1 + k2) ] A
 
Answered by Thiyagarajan K | 29 Nov, 2019, 09:31: AM

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