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solution of 12th question
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM

Numbers written as potential on plates of capacitor is not clearly visible .

Hence procdure of answering the questions are given below

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If one plate is at a potential V1 and other plate is at a potential V2 , then electric field intensity E between plates is

E = ( V1 - V2 ) / d   ...................................(1)

where d is distance between plates of capacitor.

Force F acting on charge q  kept in the electric field E is

F = q E  ................................(2)

Hence find out the electric field between the capacitor plates using equation (1)

Then calculate the force as given by eq,(2) .

Then rank according to the magnitude of force

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