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The equation of a particle executing SHM is given by x=3cos(π/2)t cm, where t is in second. The distance travelled by the particle in the first 8.5 s is

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Asked by seaborgium.00106 31st March 2020, 2:20 AM
Answered by Expert
Answer:
Equation for displacement x of particle undergoing SHM is given by,  x = 3 cos[ (π/2) t ] cm
 
From above eqn., we get amplitude A = 3 cm and Time period T is given by ,  (2π/T)t = π/2) t or T = 4 s
 
Distance travelled in T = 8.5 s equals distance of two full cycles i.e., (2×12) cm and distance travelled in 0.5 s
 
distance travelled in 0.5 s,  x= 3 cos(π/4) = 3/√2
 
Hence the total distance travelled in 8.5 s = 24 + ( 3/√2 ) cm
 
Answered by Expert 31st March 2020, 7:37 AM
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