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the 4kg head of a sledge hammer is movingat 6m/s when it strikes a spike dividng it into a log the duration of the impact is 2ms. find the time average of the impact force

Asked by 28th July 2012, 11:45 AM
Answered by Expert
Answer:
The momentum change of the hammer will be: 0- (4*6) = -24kgm/s
duration of impact, t: 2 ms
Thus time average of forvce will be : rate of change of momentum: 24/0.002 = 12000 N
Answered by Expert 28th July 2012, 2:25 PM
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