Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 9 Answered

Questions 23-25 are based on the information given below. Read the information and answer the questions that follow:A bob of mass ‘m’ is suspended by a string, g be the acceleration due to gravity the bob.When the bob is stationary, the tension ‘T’ in the string is T=mg.When the bob is pulled up with an acceleration ‘a’ the tension in the string is given by T= m (g + a)When the bob is allowed to move down with an acceleration ‘a’, the tension T in the string is given byT= m (g –a)  
Asked by avishisanghai | 20 Feb, 2022, 05:19: PM
answered-by-expert Expert Answer
Let m is mass of the bob , g is acceleration due to gravity and T is tension force in the string .
 
When the bob is at rest , Net force acting on the bob is zero.
 
Hence , By applying Newton's second law , we get
 
T - mg = 0   or  T = mg
 
------------------------------------------
 
When the bob is pulled up with uniform acceleration a , then by applying Newton's second law ,
we get
 
T - mg = ma    or   T =  m ( g + a)
 
-------------------------------------------------------------------
When the bob is moved down with uniform acceleration a , then by applying Newton's second law ,
we get
 
mg - T = ma    or   T =  m ( g - a)
Answered by Thiyagarajan K | 20 Feb, 2022, 08:02: PM

Concept Videos

CBSE 9 - Physics
Asked by vomtimittagurupriya | 29 Sep, 2023, 05:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by kunaljat51 | 24 Jul, 2022, 10:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mina.sengupta.2014 | 02 Sep, 2021, 12:49: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by kishor.kp14 | 24 Sep, 2019, 11:16: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by arti.iuac | 06 Mar, 2019, 11:13: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×