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a body of mass 5kg starts and roll down 32m of aninclined plane in 4sec,find the force acting on the body
Asked by kishor.kp14 | 24 Sep, 2019, 11:16: AM
answered-by-expert Expert Answer
Initial velocity u=o, because the body was released
distance travelled= 32m
time=4 seconds
s equals u t plus 1 half a t squared 32 equals 0 cross times 4 plus 1 half cross times a cross times 4 squared a equals 4 m s to the power of negative 2 end exponent F o r c e space a c t i n g space a l o n g space t h e space i n c l i n e d space p l a n e equals m a F equals 5 cross times 4 equals 20 N
Answered by Utkarsh Lokhande | 24 Sep, 2019, 12:48: PM

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