CBSE Class 8 Answered
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Asked by rahulagar2 | 07 Apr, 2024, 01:21: PM
Expert Answer
If a 5-digit number 4368x, is divisible by 11 then x is equal to:
(a) 1 (b) 2 (c) 3 (d) 4
Solution:
Sum of digits at odd positions = 3+8 = 11
Sum of digits at even positiins = 4 + 6 + x = 10 + x
Difference = 11 - (10+x) = 1-x
Difference must be 0 or 11.
When 1 - x = 0, we get x = 1
When 1 - x = 11, we get x = 12, which is not possible as x is a digit.
Hence, x = 1
Answered by Renu Varma | 10 Apr, 2024, 04:45: PM
Concept Videos
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Divisibility Rules
Divisibility by 2, 3, 4, 6, 7, 8, 9, 10, 11, 12, 14 and 15
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