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# solve

Asked by eknathmote50 8th May 2019, 10:39 AM
Let the incident light ray makes the angle θ at B on a glass sphere.
If angle of refraction for refracted ray at B is r , then angle of incidence at C also r, because ΔOBC is isoceless.
At C, angle of reflection will be r. Hence angle of emergence at C is (90-r), because emergent ray and reflected ray
are perpendicular to each other.

At the point C, by law of refraction, we have  sin(90-r)/sin(r)  = √3   or tan(r) = 1/√3  or r = π/6

At the point B,  sin(θ)/sin(r) = sin(θ)/sin(π/6) = √3    or  sin(θ) = √3 /2  or  θ = π/3
Answered by Expert 8th May 2019, 3:01 PM
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Tags: refraction

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