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Asked by eknathmote50
8th May 2019,
10:39 AM
Answered by Expert
Answer:
Let the incident light ray makes the angle θ at B on a glass sphere.
If angle of refraction for refracted ray at B is r , then angle of incidence at C also r, because ΔOBC is isoceless.
At C, angle of reflection will be r. Hence angle of emergence at C is (90-r), because emergent ray and reflected ray
are perpendicular to each other.
At the point C, by law of refraction, we have sin(90-r)/sin(r) = √3 or tan(r) = 1/√3 or r = π/6
At the point B, sin(θ)/sin(r) = sin(θ)/sin(π/6) = √3 or sin(θ) = √3 /2 or θ = π/3
Answered by Expert
8th May 2019,
3:01 PM
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