CBSE Class 12-science Answered
solve it
Asked by rp978841 | 08 May, 2024, 09:01: PM
Expert Answer
The circuit is redrawn and shown above. We see that resistors R2, R3 and R4 are in parallel .
Equivalenet resistance of R2, R3 and R4 is
Hence, Equivalent resistance of circuit is ( 6 + 4 ) Ω = 10 Ω .
Current drawn from battery = 10 V / 10 Ω = 1 A
Current through resistor R1 = 1 A ;
Potential difference across R1 = ( 1 A × 4 Ω ) = 4 V
Potential difference across A and B = ( 10 - 4 ) V = 6 V
Current through R2 = 6 V / 15 Ω = 0.4 A
Current through R3 = 0.4 A
Current through R4 = 6 V / 30 Ω = 0.2 A .
Answered by Thiyagarajan K | 09 May, 2024, 07:58: AM
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